13x^2+4x+-3=7

Solution for 13x^2+4x+-3=7 equation:

13x^2+4x+-3=7

We move all terms to the left:

13x^2+4x+-3-(7)=0

determiningTheFunctionDomain
13x^2+4x-3-7+=0

We add all the numbers together, and all the variables

13x^2+4x=0

a = 13; b = 4; c = 0;
Δ = b2-4ac
Δ = 42-4·13·0
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4}{2*13}=\frac{-8}{26}
=-4/13
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4}{2*13}=\frac{0}{26}
=0
$